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===Full Explanation=== Crater formation is easy to see and understand. An object comes in from outer space, strikes a planet or moon, and that impact results in a hole on the surface. However, the dimensions of the crater formed, and what factors into the dimensions of it, are a bit harder to comprehend. When we drop a ball into the sand, and as we drop it from higher heights, we can see the three stages of crater formation happening. We first see what is called the '''Contact Stage''', when it first strikes the surface. The ball will sink into the surface, compressing some of the sand, and creates a pressure wave in the sand itself. As this pressure wave travels out through the sand, it pushes some of the sand around the ball up and away from the impact. This is the '''Excavation Stage''', when we see the bits of sand being flung up around the ball, and we see the crater's width form. Right after this we see the '''Modification Stage''', when some of the sand forming the crater wall collapses into it, finishing the shape and size of the crater. When we drop the ball from differing heights, we are affecting how much energy it has when it strikes the sand. In this case, we are looking at the relationship between '''Potential Energy''' (''PE = mgh'') and '''Kinetic Energy''' (''KE = 1/2 mv^2''); By increasing the drop height, we are increasing the final velocity of the ball, which affects the final dimensions of the crater. When a crater forms, the initial crater before any collapse will normally be spherical, and will have a depth and width that are proportional to the size of the object. If we measure the width and depth of the craters formed by the balls in the sand, we should start to see a trend that both of these factors are increasing. They both increase slowly, however, with the width of the crater growing faster than the depth of it. This is because of the spherical shape a crater takes on; the volume of a sphere can be calculated with a cubed diameter, and the crater formed will never have a volume greater than 1/3 of an imaginary sphere placed within it. We can combine these terms to find: {| class="wikitable" style="color:black; background-color:#ddd; text-align: center; margin: auto" | '''Diameter d<sup>1/3</sup>''' | '''β''' | '''1/2 mv<sup>2</sup>''' = '''mgh''' |- | '''Depth d<sup>1/4</sup>''' | '''β''' | '''1/2 mv<sup>2</sup>''' = '''mgh''' |} If we want to see the crater from the two foot drop get twice as wide, we would have to drop it from eight feet high! Also, in order to see the crater get twice as deep, we would have to drop the ball from sixteen feet! If we drop objects from the edge of the atmosphere, however, they will reach a max velocity because of the air slowing it down. In that case, we would instead have to adjust the object's mass is in order to see larger craters. This is why little meteoroids falling to earth don't usually leave a mark, but bigger ones will!
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